Mathematics, 23.10.2020 21:10 Trendymwah9738

Given: PQ | P’Q’ Prove: (m PQ) (m P’Q’) = -1
1. m PQ = y2-y1/x2-x1 = [spade]/c-a
[spade] =
2. m P’Q’ = y2-y1/x2-x1 = c-a/[heart]
[heart] =
3. m P’Q’ = c-a/-d-(-b) = c-a/[spade]
[spade] =

Answers: 1

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Given: PQ | P’Q’ Prove: (m PQ) (m P’Q’) = -1
1. m PQ = y2-y1/x2-x1 = [spade]/c-a
[spad...

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More questions: Mathematics Another questions

Given: PQ | P’Q’ Prove: (m PQ) (m P’Q’) = -1 1. m PQ = y2-y1/x2-x1 = [spade]/c-a [spade] = 2. m P’Q’ = y2-y1/x2-x1 = c-a/[heart] [heart] = 3. m P’Q’ = c-a/-d-(-b) = c-a/[spade] [spade] =

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Another question on Mathematics

Given: PQ | P’Q’ Prove: (m PQ) (m P’Q’) = -1
1. m PQ = y2-y1/x2-x1 = [spade]/c-a
[spade] =
2. m P’Q’ = y2-y1/x2-x1 = c-a/[heart]
[heart] =
3. m P’Q’ = c-a/-d-(-b) = c-a/[spade]
[spade] =