What is the equation of the line that is perpendicular to y = one-fifth x + 4 and that passes through (5,–4)? y = negative 5 x minus 29
y = negative 5 x + 21
y = one-fifth x minus 4
y = one-fifth x minus 5

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

the answer is mp

step-by-step explanation:

is there a question here?

step-by-step explanation:

3 3 6, because in every triangle the longer side is always shorter than the sum of the other two