In a lottery game, a player picks six numbers from 1 to 28. If the player matches all six numbers, they win 20,000 dollars. Otherwise, they lose $1. What is the expected value of this game?

There are 23C6 ways to pick 6 numbers from 23; the probability of any particular one is just shy of 1/100000.

There are 23C6 ways to pick 6 numbers from 23; the probability of any particular one is just shy of 1/100000.Thus the expectation for winning is about $0.30 and losing very close to $1...the t total expectation is about -$0.70.

There are 23C6 ways to pick 6 numbers from 23; the probability of any particular one is just shy of 1/100000.Thus the expectation for winning is about $0.30 and losing very close to $1...the t total expectation is about -$0.70.You can calculate the exact number by using the exact probability of picking the winning number stated in the first line of this answer.

Step-by-step explanation:

I hope it's helpful

if im undersanding the question correctly, its organized from 10

step-by-step explanation:

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3