The sum of two consecutive integers is no more than 209. what is the larger of the two integers? enter your answer in the box.

The answer to your question is: 105

Step-by-step explanation:

For this problem we have to find to integers that when we sum them the result not be larger than 209. So, we need to write an equation to find them.

The integers we are looking for are:

The lower number = x

The larger number = x +1  because they are consecutive

The equation would be

                                       (x) + (x+1) = 209        and we solve it

                                         x + x +1 = 209

                                         2x = 209 - 1

                                         2x = 208

                                           x = 208/2

                                            x = 104          the lower number

   Then the larger number is: x + 1 = 104 + 1 = 105

answer: t=3

step-by-step explanation:

step-by-step explanation:

a rhombus is a parallelogram enjoying his symmetry.