Consider rhombus G H I J with diagonals IG and HJ

Option (1)

Step-by-step explanation:

Properties of the angles of a rhombus:

1). Diagonals are perpendicular.

2). Opposite angles are equal in measure.

3). Diagonals bisect the angles at the vertices.

Given: m∠GJH = 18°

In ΔGJH,

m∠GJH + m∠GHJ + m∠JGH = 180°

m∠GJH + m∠GJH + m∠JGH = 180° [Since, ∠GJH ≅ ∠GHJ diagonals bisect the opposite angles and opposite angles are equal in measure]

2m∠GJH + m∠JGH = 180°

2(18)° + m∠JGH = 180°

m∠JGH = 180° - 36°

             = 144°

Since, opposite angles of a rhombus are equal,

m∠JGH = m∠JIH = 144°

Option (1) will be the answer.

oof tough question

step-by-step explanation:

sorry i can't ya : c gl tho

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.