WILL GIVE BRAINLIEST! Find an equation of the circle and sketch it if it has: Tangent to y-axis, r=5, contains (10, 7)

Center = (5,7)

Radius = 5

Explanation:

The circle must be tangent to the y axis, and it has a radius of 5, so that means the center (h,k) must either be on the line x = 5 or x = -5, since those vertical lines are exactly five units away from the y axis.

But we're also told that (10,7) must be on the circle. That rules out x = -5 because the distance from (10,7) to (-5,k) is going to be larger than 5. I recommend drawing out a right triangle to see why this is the case.

So the center (h,k) must be on the line x = 5.

The center is the point (h,k) = (5,k)

Plug that h value along with (x,y) = (10,7) and r = 5 into the equation below

Solve for k.

(x-h)^2 + (y-k)^2 = r^2

(x-5)^2 + (y-k)^2 = 5^2 plug in h = 5 and r = 5

(10-5)^2 + (7-k)^2 = 25 ... plug in x = 10 and y = 7

25 + (7-k)^2 = 25

(7-k)^2 = 25-25

(7-k)^2 = 0

7-k = sqrt(0)

7-k = 0

-k = 0-7

-k = -7

k = 7

The center is (h,k) = (5,7)

We have (x-h)^2 + (y-k)^2 = r^2 updating to (x-5)^2 + (y-7)^2 = 25

step-by-step explanation:

first, eliminate the parenthesis:

3

x

+

2

−

4

x

second, group like terms:

3

x

−

4

x

+

2

third, combine like terms:

(

3

−

4

)

x

+

2

→

−

1

x

+

2

→

−

x

+

2