Prove that the sum of the measures of angles of a truangle is 180°

to prove that the sum of the triangles is equal to 180 degree

we have to take three angles angle 1 2 and 3 angle 1 is equal to angle p angle 2 = q and angle 3 is equal to r

and we have to prove that angle 1 + angle 2 + angle 3 is equals to 180 degree

construction draw a line xy passing through

p parallel to QR

proof

for for lines xy and QR with transversal PQ x p q is equals to4 and YPR is equals to angle5

so angle 2 is equal to angle 4 alternative angles

angle 5 is equal to angle 3 alternative angles

also fore line xy angle 1 + angle 4 + angle 5 is equals to 180 degree

and angle 1 + angle 2 + angle 3 is equal to 180 degree

hence sum of all triangles is equal to 180 degree

hence proved

center= (-2,0)

radius= sqrt2/2

step-by-step explanation: