A piece of wire 10 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral triangle. Find the maximum and minimum possible area that can be enclosed by the wire.

Given :

A piece of wire 10 m long is cut into two pieces.

To Find :

One piece is bent into a square and the other is bent into an equilateral triangle.

Solution :

So, perimeter of triangle is 5 m :

Area of triangle of side a :

Now. we know maximum area of a given perimeter is for equilateral triangle.

3s = 5

Hence, this is the required solution.

$53.50

step-by-step explanation:

you have to subtract the amount of money chuck earned ($72.50) by the cost of the gas for the mower ($11.25) and the new string for the trimmer he bought ($7.75).

72.50-11.25=61.25

and then subtract $61.25 by the second thing he bought (the new string for the trimmer)

61.25-7.75=53.5

so in total it's $53.50 (53 dollars and 50 cents)

constants mean the stopped points or the points on a graph that nothing is changing, hope this

step-by-step explanation: