The paraboloid z = 3 − x − x2 − 2y2 intersects the plane x = 1 in a parabola. Find parametric equations in terms of t for the tangent line to this parabola at the point (1, 3, −17). (Enter your answer as a comma-separated list of equations. Let x, y, and z be in terms of t.

the required parametric equation is:

x = 1

y = t + 3

z = -12t - 17

Step-by-step explanation:

From the given information:

We are to express x,y, and z in terms of t.

The purpose of this question is to find the parametric equations in terms of t.

Given that the tangent line related to the parabola is the point (1,3, -17)

Provided that the paraboloid z = 3 - x - x² - 2y² intersect the plane x = 1 in a paraboloid; then:

z = 3 - 1 - (1)² - 2y²

z = 1 - 2y²

Suppose y = t, then the parametrization is given by:

(x (t), y(t), z(t) ) = (1, t, 1 - 2t²)

(x' (t), y'(t), z'(t) ) = (0,1, -4t)

At the point (x,y,z) = (1,3, -17)

For t (=y) = 3

Hence, (x'(3),y'(3),z'(3)) = (0,1, -12)

Therefore, the equation of the tangent line can be expressed as:

x - 1 = 0, y -3 = t, z + 17 = -12t

x = 1, y = t + 3 , z = -12t - 17

Thus, the required parametric equation is:

x = 1

y = t + 3

z = -12t - 17

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet