Genes a, b and c are linked on a particular chromosome in this order. The distance between a and b is 9.0 map units, while b and c are 30 map units apart. What is the probability of a double crossover if interference in this chromosomal region is 70%

The  value is

Step-by-step explanation:

From the question we are told that

    The distance between a and b is  e =   9.0 map unit

    The distance between b and  c is  f = 30 map unit

      The interference in this chromosomal region is L  = 70% =  0.7

Gnerally the  first single cross-over in this chromosomal  region  is mathematically represented as

=>    

=>    

Gnerally the  first single cross-over in this chromosomal  region is mathematically represented as

=>    

=>    

Gnerally the expected double cross-over in this chromosomal  region  is mathematically represented as

=>  

=>  

Generally the coefficient of  coincidence is mathematically represented as

=>  

=>  

Generally this coefficient of  coincidence can also be mathematically represented as

Here G is  the probability of a double crossover (the observed double cross over)

So

=>  

Converting to percentage

on monday rodney ate 1/4th of the sandwich = 3/12

on tuesday he ate 1/3rd of the sandwich = 4/12

therefore in total he has eaten = 3/12 + 4/12 = 7/12

thus we can say that he has eaten 7/12 of the sandwich on monday and tuesday alltogether.

happy to

pls mark as brainliest.