Dalyn has been asked to consider the following functions: f (x) = 6x² - 12x + 11
g (x) = 6(x - 1)² + k

Dalyn would like to find a value of a k such that both f(x) and g(x) model the same graph. Help Dalyn solve for the value of k so both functions will represent the same graph.

In order that both functions to represents the same (one) graph then the value of k is 5

Step-by-step explanation:

The given functions are;

f(x) = 6·x² - 12·x + 11

g(x) = 6·(x - 1)² + k

Expanding the function g(x) gives;

6·(x - 1)² + k = 6 × (x² - 2·x + 1) + k = 6·x² - 12·x + 6 + k

∴ 6·(x - 1)² + k = 6·x² - 12·x + 6 + k

Comparing with the function for f(x), we have;

f(x) = 6·x² - 12·x + 11

g(x) = 6·(x - 1)² + k = 6·x² - 12·x + 6 + k

The difference between the two functions is the constant term, which are;

Constant term for f(x) = 11

Constant term for g(x) = 6 + k

For the two terms to describe exactly the same graph, the constant term should also be equal

We will then have, 11 = 6 + k

∴ k = 11 - 6 = 5

k = 5

For both functions to represent the same graph the value of k = 5.

step-by-step explanation:

ok one would be money, and the other would be refreshments or something similar. if each bag of popcorn is 5.00 and each drink is half of that that means drinks are 2.50 the proper way to do that would to look and see how much of each you can buy without exceeding a limit of 30.00

combine all like terms then its just a 2 step equation