Dr. Price descends to location D (-3,259 5/8) to observe shrimp. She than ascends and stops to observe sea life that is halfway between location B (-1,098 3/20) and Location C (-2,784.75) what is the total distance between location D (-3,259 5/8) and where Dr. Price stopped to observe?

(-1941.45)

Step-by-step explanation:

Given data:

Location D = (-3,259 5/8)

Location B = (-1,098 3/20)

Location C = (-2,784.75)

Solution:

Dr. Price descends to Location D (-3259.63), –ascends back to B ( -1,098.15) + location C (-2,784.75) /2 = New location (-1318.18 ).

Location D – New location

= (-3259.63) – (-1318.18 ).

=(-1941.45).

Dr. Paul is (-1941.45) distance away from location D.

mathpapa

step-by-step explanation:

the answer is 5/14.

hope this .