Find two positive and two negative angles that are coterminal with the quadrantal angle such that each angle lies between 1080 and 720

The quadrantal angles are those whose terminal side lands on an axis.

The general form of these angles is:

A = n*90°.

Where n can be any integer.

Now we want to two negative angles and two positive angles, such that the angles lie between 1080 and 720.

As the number in the left is, in absolute value, larger than 720, i guess that the segment is written as:

-1080 and 720.

This also will allow us to find the negative angles that we want.

Now, first find the positive ones.

A = n*90°

Just give n the value of positive integers, for example, 7 and 6

A = 7*90° = 630°

A = 6*90° = 540°.

And for the negative angles, we need to input negative values for n.

let's take n = -8 and -9

A = -8*90° = -720°

A = -9*90° = -810°.

And all those angles are in the given range.

step-by-step explanation:

points a and b are equidistant from the desired line, so the line you find by using them will go through point r.

using points other than a and b will give the desired line only if they are equidistant from r. if they are randomly located, the perpendicular line you create will not necessarily go through point r, hence will not be a solution to the problem.