If an investment account starts with $3900, and grows with 2.1% interest, compounded continuously. How much is the account worth after 10 years? Round your answer to the nearest dollar. Do NOT round until you have calculated the final answer.

If they are asking amount it is $4800.893013; $4800 (nearest dollar)

If they are asking the amount for interest is $900.8930129; $900 (nearest dollar)

Step-by-step explanation:

Compound interest Formula:

Amount = principle( 1+ rate/100)^n

Information from the question.

-So how you put it is the principle is $3900; the rate is 2.1%; the n is 10.

How to apply it?

- Just substitute in the values;

Amount=3900(1+2.1/100)^10

=4800.893013

~4800 ( nearest dollar)

》That is for amount.

Interest=4800.893013-3900

=900.893013

~900 ( nearest dollar)

》That is for interest.

Hope it helps:))

im a goose

step-by-step explanation:

gg5

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)