To factor 9x^2-16, you can first rewrite the expression as: A. (3x)^2-(4)^2

B. (3x-4)^2

C. (3x)^2-(4)

D. None of the above

A (3x)^2-(4)^2

In right ∆abc shown below, the midpoint of hypotenuse ac is located at d and segment bd is drawn.if ab = 12 and bc = 16, then explain why bd = 10. hint: consider what you know about the diagonals of a rectangle.

How are sas and sss used to show that two triangles are congruent?

Find the zeros of each function. f(x) = x^2 + 5x - 6