The sum of 333 consecutive even numbers is 132132132.
What is the third number in this sequence?

Let x be the first number in the sequence. Consecutive even integers are separated by a distance of 2. So

x + (x + 2) + (x + 4) = 132

3x + 6 = 132

3x = 126

x = 42

which makes the third number x + 4 = 46.

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

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step-by-step explanation: