PLEASE HELP Use the Polygon tool to draw an image of the given polygon under a dilation with a scale factor of 1/3 and center of dilation at (0, 0).

We are given : A scale factor of 1/3 and center of dilation (0, 0).

For the given image, the coordinates of the vertices of the triangle are

(0,9), (0,0) and (-6,0).

We can apply formula for finding new coordinates:

Scale factor * [Vertex coordinates of the given image - Coordinate of Center of dilation] +Coordinate of Center of dilation.

Applying same formula to each coordinates we are given.

(0,9) --> 1/3 [ (0,9) - (0,0) ] + (0,0) ]  = 1/3 [ (0,9)] +(0,0) = (0,3).

(0,0) --> 1/3 [ (0,0) - (0,0) ] + (0,0) ]  = 1/3 [ (0,0] +(0,0) = (0,0).

(0,9) --> 1/3 [ (-6,0) - (0,0) ] + (0,0) ]  = 1/3 [ (-6,0)] +(0,0) = (-2,0).

Now, we can plot those resulting coordinates on the graph and form a triangle.

Step-by-step explanation:

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form