shopkeeper sells one machine for 990 re at a profit of 10% and another machine for 1960 at a loss of 2%

The profit made is 50

Cost price of first machine will be:

= 100/(100 + 10) × 990

= 100/110 × 990

= 100 × 9

= 900

Cost price for second machine will be:

= (100 - 2) × x = 1960

= 98% × x = 1960

= 0.98x = 1960

x = 1960/0.98.

x = 2000

The total cost price = 900 + 2000 = 2900

Total selling price = 990 + 1960 = 2950

Therefore, profit will be:

= Selling price - Cost price .

= 2950 - 2900

= 50

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Complete question :

shopkeeper sells one machine for 990 re at a profit of 10% and another machine for 1960 at a loss of 2%. What is his gain or loss percent

1.72%

Step-by-step explanation:

Given that :

MACHINE 1:

Sales price = 990

Profit percent = 10%

The cost price of the machine (x) :

10% profit of x :

(100 + 10)% of x = 990

110% of x = 990

1.1x = 990

x = 990/1.1

x = 900

MACHINE 2:

Sales price = 1960

Loss on sale = 2%

Cost price (x) :

(100 - 2)% of x = 1960

98% x = 1960

0.98x = 1960

x = 1960/0.98

x = 2000

Total amount realized from sale = (990 + 1960) = 2950

Total cost of production = (2000 + 900) = 2900

Profit Made = (2950 - 2900) = 50

% profit:

(Profit / cost of production) * 100

(50 / 2900) * 100%

0.0172413 * 100%

profit % = 1.72

11.2

step-by-step explanation:

when doing tangent the tangent of the angle is equal to the opposite side from the angle over the adjacent side to the angle.

tan43 = x / 12

move 12 over by multiplying each side by 12

12tan43 = x

x = about 11.2