PLEASE HELP ME OUT I ONLY HAVE 5 MIN TO TURN THIS IN

Write an equation in slope-intercept form for the line that passes through the given point and is perpendicular to the graph of the given equation.

Equation: y-intercept of 6, 3y = 2x – 3

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Divide sides by 3

This is the slope-intercept form of the given line.

The coefficient of x in slope-intercept form of the linear functions shows the slope .

Thus the slope of the given line is ⅔ .

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Remember from now on ;

Multiply of the slopes of the lines which are perpendicular to each other equals -1.

Suppose the slope of the line which question asked is m .

So :

Multiply sides by 3

Divide sides by 2

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m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°