PLEASE HELP A rectangular pyramid has a height of 10 meters. The base measures 8 meters in length and 12 meters in width. Two different triangular cross sections are formed through the vertex and perpendicular to the base. What is the difference in the areas of the cross sections?
m²

step 1

find the area of the first cross section

area1=b1*h/2

b1=8 m

h=10 m

area1=6*10/2> 30 m²

step 2

find the area of the second cross section

area 2=b2*h/2

b2=12 m

h=10 m

area1=12*10/2> 60 m²

step 3

find the difference in the areas of the cross sections

difference=60-30> 30 m²

the answer is

30 m²

Step-by-step explanation:

the answer is 844

step-by-step explanation:

it is 844 because if you add 836.50 + 7.5 you will get 844