on sunday Danielle is having her friends over for her 9th birthday she had 24 M&M bags 36 jelly beans and 48 snickers to make goodie bags If each person coming to her party received the same amount of each candy what is the greatest number of friends that can come over how much candy will they receive PLS help due in 20 minutes

Number of M&M bags with Danielle = 24

Number of jelly beans with her = 36

Number of snickers with her = 48

To find the highest number of candies each friend of Danielle will get, in a way in which all of them have the same number of candies , we have to find the HCF (highest common factor) of all the varieties of candy with Danielle.

Factors of 24 = 1,2,3,4,6,8,12,24

Factors of 36 = 1,2,3,4,6,9,12,18,36

Factors of 48 = 1,2,3,4,6,8,12,16,24,48

Highest common factor = 12

Which means the highest number of friends Danille can invite is 12 .

Number of M&M bags each friend will get :-

Which means each friend will get 2 M&M bags .

Number of jelly beans each friend of hers will get :-

Which means each friend of Danielle will get 3 jelly beans.

Number of snickers each friend of hers will get :-

Which means each friend of hers will get 4 snickers .

Therefore , the highest number of friends Danielle can invite = 12 and each of her friends will get 2 M&M bags , 3 jelly beans and 4 snickers .

or

step-by-step explanation:

we need to solve for 'x' the following equation:  

we have that:

⇒

⇒ ⇒

factorizing, we get that:

  ⇒

then, the solutions are: or

nothing extraneous has been found!

add the numbers under frequency to find the total number:

5 + 8 +7 + 4 + 0 +1 = 25

the answer is 25.