on sunday Danielle is having her friends over for her 9th birthday she had 24 M&M bags 36 jelly beans and 48 snickers to make goodie bags If each person coming to her party received the same amount of each candy what is the greatest number of friends that can come over how much candy will they receive PLS HELP ANSWER FAST THIS IS DUE IN 30 MINUTES AND ITS HALF OF MY GRADE

Number of M&M bags with Danielle = 24

Number of jelly beans with her = 36

Number of snickers with her = 48

To find the highest number of candies each friend of Danielle will get, in a way in which all of them have the same number of candies , we have to find the HCF (highest common factor) of all the varieties of candy with Danielle.

Factors of 24 = 1,2,3,4,6,8,12,24

Factors of 36 = 1,2,3,4,6,9,12,18,36

Factors of 48 = 1,2,3,4,6,8,12,16,24,48

Highest common factor = 12

Which means the highest number of friends Danille can invite is 12 .

Number of M&M bags each friend will get :-

Which means each friend will get 2 M&M bags .

Number of jelly beans each friend of hers will get :-

Which means each friend of Danielle will get 3 jelly beans.

Number of snickers each friend of hers will get :-

Which means each friend of hers will get 4 snickers .

Therefore , the highest number of friends Danielle can invite = 12 and each of her friends will get 2 M&M bags , 3 jelly beans and 4 snickers .

step-by-step explanation:

30% of $420 is 0.30($420) = $126 and $420 + $126 = $546.

or, 130% of $420 is 1.3($420) = $546.

notice that this is not the $600 original list price with which we started.

why doesn't this work?

the method does not work because 30% of $420 is not the same amount as the 30% of $600. it may seem obvious when stated this way, but it is a very common error made on problems of this type. we cannot just use the same percent and get back to the original amount because we are taking that percent of a different value.

to work problems of this type correctly, it is generally best to write an equation for the situation and then solve.

example: since (100% – 30%)(original price) = (sale price)

70% of the   (original price) is $420.

0.7x   = 420

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x = 600

the original cost was $600.

we may also solve this problem using the two-step method. working the problem in two steps requires us to use more algebra skills. we have to know that x = 1x (identity property of multiplicationtext annotation indicator) and that 1x – 0.3x = 0.7x (subtracting like terms). then we solve the problem as follows:

(original price) – 30%(original price) = sale price

x – 0.3x = 420

0.7x = $420

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x = 600

the original cost was $600.  

note that with both of the above methods we do obtain the correct original amount.

example: after a 5% pay raise, hermione is earning $22,680 per year. what was she earning before the pay raise?

105% of (original salary) = current salary

1.05x = 22,680

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x = 21,600

hermione earned $21,600 per year before the pay raise.

this is an example so maybe you will get how to at least do it!