Summer and Autumn are friends who live 25 miles apart and they are training for a long race. On wednesday after school, they ran toward each other’s houses to meet up. They left their houses at 4pm and met at 6 pm. Summer ran an average rate of 8 1/2 miles per hour

Complete question is;

Summer and Autumn are friends who live 25 miles apart and they are training for a long race. On wednesday after school, they ran toward each other’s houses to meet up. They left their houses at 4pm and met at 6 pm. Summer ran an average rate of 8 ½ miles per hour faster than autumn. What is the average speed of each?

Autumn's average speed is 1.3158 mph

Summer's average speed is 11.1843 mph

Step-by-step explanation:

We are told that they live 25 miles from each other.

They left their houses at 4pm and met at 6 pm. This means they met 2 hours later.

Now, summer ran 8.5 mph faster than autumn.

This means if autumn's speed is "x", then summer ran 8.5x mph

Thus, total distance covered by summer is; d_summer = 8.5x * 2 = 17x

Total distance by autumn is; x * 2 = 2x

Since their houses are 25 miles apart.

Thus;

17x + 2x = 25

19x = 25

x = 25/19

x = 1.3158 mph

Thus, autumn's speed is 1.3158 mph

Summer's speed is 1.3158 × 8.5 = 11.1843 mph

explanation:

previous steps have made pa≅ pb ≅ st ≅ su. setting the compass width to ab allows you to make tu the same length. then δstu ≅ δpab by the sss congruence postulate, and ∠p ≅ ∠s by the reason cpctc.

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step-by-step explanation: