A machine fill bags with cement. Assume the actual masses of the bags have a normal distribution. If the standard deviation of the amount dispensed is 1.1 lb and the mean is set to 50 lb. What proportion of bags have a mass more than 50.4 lb? (2 p

0.35808

Step-by-step explanation:

Given a normal distribution :

Mean (m) = 50 lb

Standard deviation (σ) = 1.1 lb

Proportion of bags with mass more than 50.4 lbs

X : X > 50.4 lbs

Using the Zscore relation :

Zscore = (x - m) / σ

Zscore = (50.4 - 50) / 1.1

Zscore = (0.4) / 1.1

Zscore = 0.3636363

P(Z > 0.3636) = 1 - P(Z < 0.3636)

P(Z < 0.3636) = 0.64192

1 - P(Z < 0.3636) = 1 - 0.64192 = 0.35808

whats the question?

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204