the prices of stock A at 9am was $12.18 since then the price has been increasing at the rate of $0.06 each hour. At noon the price of stock B was $12.68. It begins to descrease at the rate of $0.09 per hour. If the 2 rates continue in how many hours will the prices of the two stocks be the same?

3.33hours

Step-by-step explanation:

Where the number of hours = h

the prices of stock A at 9am was $12.18 since then the price has been increasing at the rate of $0.06 each hour.

The Algebraic expression =

$12.18 + $0.06 × h

12.18 + 0.06h

At noon the price of stock B was $12.68. It begins to descrease at the rate of $0.09 per hour.

$12.68 - $0.09×h

12.68 - 0.09h

If the 2 rates continue in how many hours will the prices of the two stocks be the same?

Stock A = Stock B

12.18 + 0.06h = 12.68 - 0.09h

Collect like terms

0.06h + 0.09h = 12.68 - 12.18

0.15h = 0.5

h = 0.5/0.15

h = 3.3333333333 hours

h = 3.33hours

ddsf

step-by-step explanation:

dfs

the answer is d

step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

  -3         -3  

y=-4x+5