Acompany plans to sell pens for $2 each. the company’s financial planner estimates that the cost, y, of manufacturing the pens is a quadratic function with a y-intercept of 120 and a vertex of (250, 370). what is the minimum number of pens the company must sell to make a profit?

Option B is correct

The minimum number of pens the company must sell to make a profit is, 174.

Explanation:

Let x be the number of pens  and y be the cost of the pens.

To find the cost of the equation.

It is given that cost , y , of manufacturing the pens is a quadratic function i.,e

                [1]

and  y-intercept of 120 which means that for x=0 , y=120 and Vertex = (250 , 370).

Put x = 0  and y =120  in [1]

120 = 0+0+c

⇒  c= 120.

Since, a quadratic function has axis of symmetry.

The axis of symmetry is given by:

                [2]

Substitute the value of x = 250 in [2];

or

                        [3]

Substitute the value of x=250, y =370, c =120 and b = -500 a in [1];

 or

or

or

1 = -250 a

⇒

We put the value of a in [3]

So,

b =-500 a=

Simplify:

b =2

Therefore, the cost  price of the pens is:  

And the selling  of the pens is 2x [ as company sell pens $ 2 each]

To find the minimum number of pens the company must sell to make a profit:

profit = selling price - cost price

Since to make minimum profit ; profit =0

then;

or

Simplify:

⇒   or

Simplify:

x =173.205081

or

x = 174 (approx)

Therefore, the minimum number of pens the company must sell to make a profit is, 174

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116