The maximum walking speed S, in feet per second, of an animal can be modeled by the equation S = L, where g = 32 ft/sec and L is the length in feet, of the animal's leg. To the nearest
hundredth, how many times greater is the maximum walking speed of a giraffe with a leg length of 6
feet than a hippopotamus with a leg length of 3 feet?
0.71 times
4.06 times
1.41 times
2.00 times

the solution is x=1

step-by-step explanation:

we are given our   equation as

let's assume

left side function is

right side function is

now, we can draw graph

and then we can get intersection point

the intersection point will be solution

so, the solution is

x=1

i would be 2,000 just get the square root of 50 which is 2500 and the divid 4/5 and last thing multiply the answer you get for that by the square root of 50

step-by-step explanation:

answer: graph 2

step-by-step explanation: