In set-builder notation, how do you write the solutions of 2x − 7 ≥ 11? A. {x|x ≥ 2}
B. {x|x ≤ 9}
C. {x|x ≥ 9}
D. {x|x ≤ 2}

Acompound inequality is graphed, and its graph consists of all real numbers. which open scentence could have resulted in this solution set r> 3 or r< -2. r< 3 or r< -2. r> 3 or r> -2. r< 3 or r> -2 plz asap