-10 What is the equation of the line that is perpendicular to
the given line and passes through the point (2, 6)?
8
(2.6)
6
0 x = 2
0 x = 6
2
-10-8-6 A-22
246810 X
O y = 2
y = 6
K-8 -4
-6
(8.4)
8
10

x/3-10=8

x/3=18

x=48

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

factor trees are nice.

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92