I NEED HELP ASAP PLEASE ANSWER FULLY WITH WORK A red ball rolls for 6 meters across a sticky level surface and slows down to a stop. the ball was rolling at 36 meters per second when it began to roll across the sticky surface. find the acceleration, velocity final, the velocity initial, the velocity average, the distance the ball rolled, and the time of the balls roll across the sticky surface

Please find the answer in the explanation

Step-by-step explanation:

Given that a red ball rolls for 6 meters across a sticky level surface and slows down to a stop. the ball was rolling at 36 meters per second when it began to roll across the sticky surface. To find the acceleration, let us use third equation of motion

V^2 = U^2 + 2as

As the object is moving to stop, V = 0

0 = U^2 - 2as

36^2 = 2 × a × 6

1296 = 12a

a = 1296 / 12

a = 108 m/s

The velocity final = 0

The velocity initial = 36 m/s

the velocity average = (36 + 0)/2

Average velocity = 36/2 = 18m/s

the distance the ball rolled = 6m

and the time of the balls roll across the sticky surface will be achieved by using first equation of motion

V = U + at

V = 0

0 = 36 - 108t

108t = 36

t = 36 / 108

t = 0.3 seconds

what

both graphs increase on their domain

neither graph has a y-intercept

step-by-step explanation:

the following points can be visualized easily from the graph