Tangela earns the same amount each week by babysitting. When she started this job, she had $200 in her savings account. The table shows Tangela's savings account balance for her first month of work. Week 0 1 2 3 4 Balance $200 $350 $500 $650 $800 Let x represent the number of weeks Tangela has been working and let y represent Tangela's account balance. Which equation, expressed in Slope-Intercept form, represents the amount of money in Tangela's bank account over time? y=150x+200

y=200x−150

y=150x−200

y=200x+150

y=150x+200

Step-by-step explanation:

Given that:

Week : 0___ 1 ___ 2 3 4

Balance : __200_350 _ 500 _ 650 ___800

Amount had in savings account = $200 before starting the job

x = number of weeks spent working

y = account balance

Slope intercept formula :

y = mx + c

C = intercept ; value of y when x = 0 = 200

m = slope or gradient = change in salary per month (350 - 200 = 500 - 350 = 650 - 500 = 800 - 650 = 150

Hence,

y = 150x + 200

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

the answer would be 484

step-by-step explanation:

just multiply 0.484 times 1,000 (formula)