Please help me I’m stuck in this class work for a while

Step-by-step explanation:

Use y=mx+b so do y1-y2 over x2-x1 to get the slope then do y=m(slope)x+b and whatever number you get from doing slope(x-x1) you substitute your x1 with the number and subtract or add to get y=slope + whatever number you have left after you did the inverse on both sides

for example: y=-2x-3.

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )