Solve the system of equations.

5x +2y = 12
5x −2y = 28

I used elimination. so you start by adding the 2 equations. |5x+2y=12+5x-2y=28| you end up getting |10x=40| the 2y’s cancel out because on is positive and one is negative. then you divide each side by 10. |x=4| you plug this in for x in the first equation. |5x+2y=12|=|5(4)+2y=12| multiply parentheses. |20+2y=12| subtract 20 from each side. |2y=12-20| add like terms. |2y=-8| divide by 2 on each side. |y=-4|. sorry for the long explanation. in conclusion, x=4 and y=-4, or (4,-4)

hope this helps :)

Ithink ghe answer to this question is b just trying to others