Classify the sequences of transformations based on whether or not they prove the congruency of the shapes by mapping shape I onto shape II. a reflection across the y-axis, followed
by a 90° clockwise rotation about the
origin, and then a translation left 18 units
a 90 clockwise rotation about the
origin and then a translation left 18 units
90° counterclockwise rotation about
the origin, followed by a resetion
across the y-axis, and then a
translation left 18 units
a 90 clockwise rotation about the
origin, followed by a reflection across
the y-axis, and then a translation
right 2 units
a 180 rotation about the origin
followed by a reflection across the
yaxis, and then a 90 clockwise
rotation about the angin
a reflection across the y-axis, followed
by a 90 counterclockwise rotation
about the origin, and then a translation
nght 2 units
Maps Shape Ionto Shape il
Does not Map Shape Ionto Shape II

I am on Edmentum, this should help you:

Maps Shape 1 to Shape 2:

A, D, and B

Does not map shape 1 to shape 2:

C, E, and F

Step-by-step explanation:

Sequence 1, a 90° clockwise rotation about the origin, followed by a reflection across the x-axis, and then a translation 4 units down and 6 units left, maps shape I onto shape II.

Sequence 2, a reflection about the y-axis of shape I and then a 90° clockwise rotation about the origin gives a shape that has the same orientation and direction as shape II. Translating this shape 4 units down and 6 units left maps shape I onto shape II.

Sequence 6, a 90° clockwise rotation of shape I about the origin, gives a shape that has the same orientation and direction as shape II. Translating this shape 16 units up and 6 units left maps shape I onto shape II.

Sequences 3, 4, and 5 do not map shape I onto shape II.

step-by-step explanation:

6.48/4 4 goes into 6.48 1.62 times

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!