What is the slope of a line perpendicular to the line whose equation is 10x - 12y = -24. Fully reduce your answer.

The slope of the line perpendicular to the line whose equation is

10x - 12y = -24 is - 6 / 5

The slope intercept form is represented as follows;

y = mx + b

where

m = slope

b = y-intercept

Therefore,

10x  - 12y = -24

10x + 24 = 12y

12y = 10x + 24

divide through by 12

12y / 12 = 10 / 12 x + 24 / 12

y = 5 / 6 x + 2

The slope of this equation is 5/6.

For a line perpendicular to another line the product of there slope is negative 1. Therefore,

m₁m₂ = -1

m₁ 5/6 = -1

m₁ = - 6 / 5

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The slope of the perpendicular line is

Step-by-step explanation:

The form of the linear equation is y = m x + b, where

∵ The equation of the given line is 10x - 12y = -24

→ We need to form this equation as the form above to find m

→ Subtract 10x from both sides

∵ 10x - 10x - 12y = -24 - 10x

∴ - 12y = -24 - 10x

→ Divide both sides by -12

∴

∴ y = 2 - () x

→ Remember that (-)(-) = (+)

∴ y = 2 + x

∵ y = m x + b

∴ m =  

∴ The slope of the given line is  

→ To find the slope of the perpendicular line reciprocal it and change

  its sign

∵ The reciprocal of    is  

→ Change its sign from + to -

∴ The slope of the perpendicular line is  

answer: '

the distance between points l and m

step-by-step explanation:

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )