A person invested $6,000 in an account growing at a rate allowing the money to double every 11 years. How much money would be in the account after 19 years, to the
nearest dollar?

P(19)=$19,852

To the nearest dollar.

Step-by-step explanation:

Exponential Growth

The natural growth of some magnitudes can be modeled by the equation:

Where P is the actual amount of the magnitude, Po is its initial amount, r is the growth rate and t is the time.

We are given the condition that an investment of Po=$6,000 in an account doubles every 11 years. The final value of the investment in t=11 is P(11)=$12,000.

Substituting into the general equation:

Dividing by 6,000 and swapping sides:

Taking the 11th root:

Substituting into the formula:

Now we need to find the money in the account after t=19 years:

P(19)=$19,852

To the nearest dollar.

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step-by-step explanation:

45

step-by-step explanation:

to find a percentage, add a decimal in front and multiply it by the other number.

.25 times 180= 45