A bus is known to arrive every 10 minutes on average at a certain bus stop. You arrive at the bus stop, hoping to catch the bus. How long are you expected to wait for the bus

10 minutes maximum

Step-by-step explanation:

well, based on the condition/fact that the bus takes and average of 10 minutes to arrive at a bus stop, you can assume that the previous bus just left(that is worst case scenario), so might have to weight for 1o minutes to get a bus.

Hence for the worst case it is expected that you would have to wait for 10 minutes maximum for the next bus to arrive, or you might even wait for a shorter time.

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

00

step-by-step explanation: