The percent of fat calories that a person in America consumes each day is normally distributed with a mean of about 36 and a standard deviation of about 10. Suppose that 16 individuals are randomly chosen. For the group of 16, find the probability that the average percent of fat calories consumed is more than thirty-five (Round to 3 decimal places)

Step-by-step explanation:

Mean μ = 36

standard deviation σ = 10

n = 16

standard deviation of the group σ₁ = σ / √n

σ₁ = 10/ √16

= 10 / 4 = 2.5

σ₁  = 2.5

P ( x > 35 ) = 1 - P ( x < 35 )

P ( x < 35 ) = P( z < (35 - 36) / 2.5 ) = P( z < (35 - 36) / 2.5 )

= P( z < 0.4  )

= .3446

P ( x > 35 ) = 1 - .3446

= .6554 .

a 4/6 = 9/12   not proportional

step-by-step explanation:

to find which are not proportional, we can use cross products

if it is true, they are proportional.   if it is not true, they are not proportional.

a 4/6 = 9/12

4* 12 = 6*9

48 = 54

not this is not proportional  

b 2/3 = 12/18  

2* 18 = 3 * 12

36 = 36

this is proportional

c 5/4 = 10/8  

5*8 = 4*10

40 = 40

this is proportional

d 7/5 = 35/25

7*25 = 5 * 35

175 = 175

is proportional

she will travel a distance in the range of 3 - 11 miles