A polar bear was sitting on the top of an ice float that was 2.5 meters above the surface of the water. The polar bear dove 6.5 meters from the top of the float into the water to catch a seal. Relative to the surface of the water, which equation best represents how far below the surface the polar bear dove?

Step-by-step explanation:

Let the surface of the water be at 0m

If a polar bear was sitting on the top of an ice float that was 2.5 meters above the surface of the water, the distance between the ice float and the surface of the water will be:

= 2.5 - 0

= 2.5m

If the polar bear dove 6.5 meters from the top of the float into the water to catch a seal, to get the distance between the bear under the water to the sea level, we will use the expression:

2.5 + x = 6.5

Subtract 2.5 from both sides

2.5+x -2.5 = 6.5-2.5

x = 4.0m

Hence the equation that best represents how far below the surface the polar bear dove is 2.5 + x = 6.5 where x is the distance between the polar bear below and the surface of the water

30 miles

step-by-step explanation:

we know that 60 seconds equals 1 minute and 60 minutes 1 hour

44 ft       60 sec     60 min     158400   ft

  *   *   =

1 sec       1 min       1 hour         hour

we know that there are 5280 ft per mile

158400   ft       1 mile         30 miles

  *   =

1   hour               5280 ft     1 hour

so in 1 hour   it can travel 30 miles

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²