Which sequences of transformations confirm the congruence of shape II and shape I? a reflection of shape I across the x-axis followed by a 90° clockwise rotation about the origin
a reflection of shape I across the x-axis followed by a 90° counterclockwise rotation about the origin
a reflection of shape I across the y-axis followed by a 90° counterclockwise rotation about the origin
a reflection of shape I across the y-axis followed by a 90° clockwise rotation about the origin
a reflection of shape I across the x-axis followed by a 180° rotation about the origin

we have three similar triangles, because each has a right angle and shares an angle.   let's write the angles in order: opposite to short leg, long leg, hypotenuse.

cab similar to bad similar to cbd

or as ratios,

ca: ab: cb = ba: ad: bd = cb: bd: cd

we also know

ac = ad + cd

(ad+cd): ab: cb = ba: ad: bd = cb: bd: cd

(ad+cd)/cb=cb/cd

we have cb=6, ad=5 and seek x=cd.

we reject the negative root and conclude x=4

answer: 4

answer: y=0 if that is what u r looking for

the arc length is found by finding the circumference of the full circle (2xpixradius) and then dividing by 4 to find just one quarter of the circle (90 degrees).

this linear equation would have just one solution.

step-by-step explanation:

the reason why this would have one solution is that it is an expression with just one variable. since that variable is not raised to a power, it will always have just one solution.