A 20 N model rocket launched vertically is clocked at 25 m/s when it is 15 m above the ground (and has expended a negligible amount of fuel). Use the work–energy principle to find the rocket’s initial speed. 27.4 m/s
40.2 m/s
17.8 m/s
30.3 m/s

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right

step-by-step explanation:

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it