Find the solution(s) of the following equation. b^2 = 49b
2
=49b, squared, equals, 49
Choose all answers that apply:
Choose all answers that apply:

(Choice A)
A
b = 7b=7b, equals, 7

(Choice B)
B
b = -7b=−7b, equals, minus, 7

(Choice C)
C
b = \sqrt{49}b=
49

b, equals, square root of, 49, end square root

(Choice D)
D
b = -\sqrt{49}b=−
49

b, equals, minus, square root of, 49, end square root

(Choice E)
E
None of the above

All of the above

Step-by-step explanation:

i just did it (also sorry it took a year for your question to be answered :(

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following