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Mathematics, 28.10.2020 18:40 moynihansavanah003
An object is launched directly overhead at 36 feet per second. The height (in feet) of the object is given by ( ) 2 ht t t =− + + 16 36 5, where t is the time (in seconds) since the object was launched. For how many seconds is the object at or above a height of 25 feet?
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An object is launched directly overhead at 36 feet per second. The height (in feet) of the object is...
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