NEED FAST:
Which number is a zero of h(x) = (x^2-81)(x+4)?
Answers given: 0, 4, 9 and 81

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Look, when you want to do something like put it like x^2. x2 could mean x² or x₂. so to clear confusion, know the notation. to find the product multiply the x's and you get -8x and the y's and you get 6y. since it's all being multiplied it is just -8x6y, or answer a. although the better answer is -48xy(combining -8 and 6) because you should multiply constants whenever you can.