ΔABC is reflected across the x-axis and then translated 4 units up to create ΔA′B′C′. What are the coordinates of the vertices of ΔA′B′C′ ? A.
A′(-3, 3), B′(-1, 1), C′(-2, 3)

B.
A′(3, -3), B′(1, -1), C′(2, -3)

C.
A′(3, -5), B′(1, -7), C′(3, -5)

D.
A′(-3, 3), B′(-1, 1), C′(-2, -3)

The missing figure is attached down

The coordinates of the vertices of Δ A'B'C' are A' (-3, 3), B' (-1, 1), C' (-2, 3) ⇒ A

Step-by-step explanation:

If the point (x, y) reflected across the x-axis , then its image is (x, -y)

If the point (x, y) translated vertically up by k units then its image is (x, y + k)

Let us solve the question using the rules above

∵ The coordinates of Δ ABC are A (-3, 1), B (-1, 3), C = (-2, 1)

∵ Δ ABC reflected across the x-axis at first

→ By using the first rule above change the signs of y coordinates

∴ The image of A = (-3, -1)

∴ The image of B = (-1, -3)

∴ The image of C = (-2, -1)

∵ Then it translated 4 units up

→ Use the second rule above, where k = 4, add each y-coordinates by 4

∴ A' = (-3, -1 + 4)

∴ A' = (-3, 3)

∴ B' = (-1, -3 + 4)

∴ B' = (-1, 1)

∴ C' = (-2, -1 + 4)

∴ C' = (-2, 3)

The coordinates of the vertices of Δ A'B'C' are A' (-3, 3), B' (-1, 1), C' (-2, 3)

your answer would be b

step-by-step explanation: