Show all work to identify the asymptotes and zero of the function f of x equals 4 x over quantity x squared minus 16.

Discontinuity of function occurs when x = 4 or x = -4

zero of function is when x=0

Step-by-step explanation:

We are given:

f(x) = 4 - x/ x^2 - 16

Discontinuity of the function occur when the denominator is equal to zero.

So, we need to find the values of x that makes the denominator zero.

The denominator is x^2 - 16

x^2 - 16 =0

x^2 = 16

x = ± 4

So, if the value of x = 4 or value of x=-4 then the function will be discontinuous.

Zero of the function i.e f(x)=0

So, Putting the function equal to zero and finding the value of x

4(x) / x^2 - 16 = 0

4(x) = 0((x)^2 - 16)

4x = 0

x = 0

So, zero of function is when x=0

0.02

step-by-step explanation:

time of 9 192 631 770 periods of the radiation corresponding to the transition between the 2 hyperfine levels of the ground state of the caesium 133 atom at 0 k (but other seconds are sometimes used in astronomy)

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