Mathematics, 29.10.2020 09:10 hermesrobles

If a-b, a+b are the zeros of x^2-4x+3 then (a, b) = A) (3, 1)
B) (-3,-1)
C) (2, 1)
D) (-2,-1)

Answers: 2

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Answers

Answer from: abbygriffin2009

Given:

α - β , α + β are the zeroes of x² - 4x + 3.

Find:

The coordinates of (a,b)

Solution:

(Let a = α & b = β).

On comparing with standard form of a quadratic equation i.e., ax² + bx + c = 0 ;

Let ;

a = 1

b = - 4

c = 3.

We know that,Sum of the zeroes = - b/a

⟹ α - β + α + β = - ( - 4)/1

⟹ 2α = 4

⟹ α = 4/2

⟹ α = 2

And,

Product of the zeroes = c/a

⟹ (α - β) * (α + β) = 3/1

(a + b) * (a - b) = a² - b².

⟹ α² - β² = 3

Putting the value of α we get,

⟹ (2)² - β² = 3

⟹ 4 - 3 = β²

⟹ 1 = β²

⟹ √1 = β

⟹ 1 = β

∴(a , b) = (α , β) = (2 , 1). (Option - C).

I hope it will help you.

Regards.

Answer from: marissastewart533

Siso your answer refer in pic

If a-b, a+b are the zeros of x^2-4x+3 then (a, b) =

A) (3, 1)
B) (-3,-1)
C) (2, 1)
D) (-2,-1)

Answer from: Quest

you answer is a

step-by-step explanation:

Answer from: Quest

x= 1

step-by-step explanation: convert 5\frac{11}{12}5

to improper fraction. use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

ac+b

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{5\times 12+11}{12}3.25+0.5x+1

5×12+11

2 simplify 5\times 125×12 to 6060

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{60+11}{12}3.25+0.5x+1

60+11

3 simplify 60+1160+11 to 7171

3.25+0.5x+1\frac{1}{3}+\frac{5}{6}x=\frac{71}{12}3.25+0.5x+1

4 simplify \frac{5}{6}x

x to \frac{5x}{6}

3.25+0.5x+1\frac{1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+1

5 convert 1\frac{1}{3}1

to improper fraction. use this rule: a \frac{b}{c}=\frac{ac+b}{c}a

ac+b

3.25+0.5x+\frac{1\times 3+1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

1×3+1

6 simplify 1\times 31×3 to 33

3.25+0.5x+\frac{3+1}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

3+1

7 simplify 3+13+1 to 44

3.25+0.5x+\frac{4}{3}+\frac{5x}{6}=\frac{71}{12}3.25+0.5x+

8 simplify 3.25+0.5x+\frac{4}{3}+\frac{5x}{6}3.25+0.5x+

to \frac{13.75}{3}+\frac{4x}{3}

13.75

\frac{13.75}{3}+\frac{4x}{3}=\frac{71}{12}

13.75

9 simplify \frac{13.75}{3}

13.75

to 4.5833334.583333

4.583333+\frac{4x}{3}=\frac{71}{12}4.583333+

10 subtract 4.5833334.583333 from both sides

\frac{4x}{3}=\frac{71}{12}-4.583333

−4.583333

11 simplify \frac{71}{12}-4.583333

−4.583333 to \frac{4}{3}

\frac{4x}{3}=\frac{4}{3}

12 multiply both sides by 33

4x=\frac{4}{3}\times 34x=

×3

13 simplify \frac{4}{3}\times 3

×3 to \frac{12}{3}

4x=\frac{12}{3}4x=

14 simplify \frac{12}{3}

to 44

4x=44x=4

15 divide both sides by 44

x=1

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If a-b, a+b are the zeros of x^2-4x+3 then (a, b) = A) (3, 1)
B) (-3,-1)
C) (2, 1)

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