A father is 30 years elder than his son. after 8 years he will be 4 times as old as his son. find their present ages

Father is 30 years older than the son.

After 8 years , he will be 4 times as old as his son.

their present ages

Let the son's age be x and age of father be y years

⟹ Father's age = Son's age + 30

⟹ y = x + 30 -- equation (1)

Also,

Son's age after 8 years = (x + 8) years.

Father's age after 8 years = (y + 8) years.

According to the above condition,

⟹ y + 8 = 4(x + 8)

⟹ y + 8 = 4x + 32

Substitute the value of y from equation (1).

⟹ x + 30 + 8 - 32 = 4x

⟹ 6 = 4x - x

⟹ 6 = 3x

⟹ 6/3 = x

⟹ 2 = x

Substitute the value x in equation (1).

⟹ y = 2 + 30

⟹ y = 32

Therefore,

Son's present age = x = 2 years.

Father's present age = y = 30 years.

I hope it will help you.

Regards.

x = 25

step-by-step explanation:

a^2+b^2=c^2

7^2+24^2=c^2

49+576=625

sqrt625=25

x=25

30 miles

step-by-step explanation:

we know that 60 seconds equals 1 minute and 60 minutes 1 hour

44 ft       60 sec     60 min     158400   ft

  *   *   =

1 sec       1 min       1 hour         hour

we know that there are 5280 ft per mile

158400   ft       1 mile         30 miles

  *   =

1   hour               5280 ft     1 hour

so in 1 hour   it can travel 30 miles