explain 18. If the likelihood of a tagged order form is 0.1, what is the probability that there are three tagged order forms in the sample of four

The probability is 0.0036

Step-by-step explanation:

Let the probability of tagged order form be p = 0.1

probability of untagged = q = 1 -0.1 = 0.9

To find the probability in the question, we apply the Bernoulli approximation of the binomial distribution

That will be;

P( X = 3) = 4 C 3 •p^3 • q

P(X = 3) = 4 * (0.1)^3 * 0.9

P(X = 3) = 0.0036

2 x^2 -3x+p

sum of roots = 3/2

let other root be x

3+ x = 3/2

x= 3/2 - 3 = -3/2

product of roots = p/2

3× -3/2 = p/2

-9 = p

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