what is the approximate probability that in a random sample of 1000 individuals who have purchased fries at McDonald’s, at least 40 can taste the difference between the two oils? (2.5 pts.)

Complete Question

In response to concerns about nutritional contents of fast foods, McDonald's has announced that it will use a new cooking oil for its French fries that will decrease substantially trans fatty acid levels and increase the amount of more beneficial polyunsaturated fat. The company claims that only 3 out of 100 people can detect a difference in taste between the new and old oils. Assuming that this figure is correct (as a long-run proportion), what is the approximate probability that in a random sample of 1000 individuals who have purchased fries at McDonald's, at least 40 can taste the difference between the two oils? (2.5 pts.)

The probability is  

Step-by-step explanation:

From the question we are told that

   The population proportion is  

    The sample size is  n  = 1000

 Generally the mean of this sampling distribution is  

Generally the standard deviation of this sapling distribution is  mathematically evaluated as  

=>      

=>      

Generally the sample proportion when the number of those that can taste the difference is 40  is mathematically represented as

Generally the approximate probability that in a random sample of 1000 individuals who have purchased fries at McDonald's, at least 40( ) can taste the difference between the two oils is mathematically represented  as

Here

=>  

From the z table the probability of  (Z < 1.85  ) is

So

So

=>

49%

step-by-step explanation:

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cause it equals more